Report for lv.id.jc.workcost.ZonePriceTest

Created on Tue Oct 25 14:34:32 UTC 2022 by runner

Executed features	Passed	Failures	Errors	Skipped	Success rate	Time
3	3	0	0	0	100.0%	0.089 seconds

Project Customer calculates the price of the zone

As the customer of the project 
I want to calculate all costs per zone
So that I be able to calculate the price of processing the zone

Issues:

should return zero if there is no any processing cost Return

(0)

Given:

surface for processing with a given area

surface.area() >> zoneArea

When:

we do not have any costs associated with the processing of the zone

def zonePrice = ZonePrice.of()

Then:

we always get zero cost of work

zonePrice.apply(surface) == 0

Where:

the surface area of the zone can be of any size

Examples:

5/5 passed

should calculate the costs for the zone with one item of expenditure Return

(0.004 seconds)

Given:

surface for processing with a given area

surface.area() >> zoneArea

And:

one item of expenses for processing the zone

def expenditure = Stub(PriceFunction) {
    apply(surface) >> expenses
}

When:

zone treatment price consists of only one expense item

def zonePrice = ZonePrice.of(expenditure)

Then:

we always get zero cost of work

zonePrice.apply(surface) == expenses

Where:

the surface area of the zone can be of any size

Examples:

4/4 passed

should calculate the costs for the zone with several items of expenditure Return

(0.041 seconds)

Given:

surface for processing with a given area

surface.area() >> zoneArea

And:

several items of expenses for processing the zone

def expenditure = expenses.collect({ cost ->
    Stub(PriceFunction) { apply(surface) >> cost }
}) as PriceFunction[]

When:

zone treatment price consists of all expenses

def zonePrice = ZonePrice.of(expenditure)

Then:

we get an accurately calculated zone treatment price

zonePrice.apply(surface) == price

Examples:

5/5 passed